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If char=1, int=4, and float=4 bytes size, What will be the output of the program ?
#include<stdio.h>

int main()
{
    char ch = 'A';
    printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));
    return 0;
}

A. 1, 2, 4 B.
1, 4, 4
C. 2, 2, 4 D. 2, 4, 8

Answer & Explanation

Answer: Option B

Explanation:

Step 1: char ch = 'A'; The variable ch is declared as an character type and initialized with value 'A'.

Step 2:

printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14));

The sizeof function returns the size of the given expression.

sizeof(ch) becomes sizeof(char). The size of char is 1 byte.

sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question).

sizeof(3.14f). The size of float is 4 bytes.

Hence the output of the program is 1, 4, 4

What is the output of the program?
#include<stdio.h>
int main()
{
    union a
    {
        int i;
        char ch[2];
    };
    union a u;
    u.ch[0] = 3;
    u.ch[1] = 2;
    printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i);
    return 0;
}

A.
3, 2, 515
B. 515, 2, 3
C. 3, 2, 5 D. None of these

Answer & Explanation

Answer: Option A

Explanation:

printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); It prints the value ofu.ch[0] = 3, u.ch[1] = 2 and it prints the value of u.i means the value of entire union size.

So the output is 3, 2, 515.